Calculation for Quantity of Cement, Sand & Coarse Aggregates

Concrete is a composite material of cement, fine sand, coarse aggregate, and water

In this article, we learn how to calculate the quantity of cement, sand, and coarse aggregates of a design mix. Below is the examples, which explain the procedure:

Manual Calculation

Calculate the approximate quantity of cement, fine sand, and coarse aggregates to prepare 1 cum of “1:1.5:3Concrete”

Data

Concrete ratio = 1:1.5:3 

Concrete volume = 1 cum

As we know the Volume of dry Concrete = is 1.55 to 1.57 times the volume of wet concrete

So total volume of required concrete will be= 1 x 1.56=1.56 cum (Assume factor as 1.56)

Calculation

Concrete Ratio = 1: 1.5: 3 Means;

Cement is in ratio 1

Fine sand is in a ratio 1.5

And coarse aggregate is in ratio 3

So total ratio will be = 1+1.5+3 = 5.5

Quantity of Cement

Quantity of Cement = Ratio of cement x volume of dry concrete / Total ratio

                                  = 1 x 1.56 / 5.5

                                 =0.284 cum

Unit weight of cement = 1400 ~ 1500 kg/cum (Assume 1450kg/cum)

1cum of cement = 1450kg

Quantity of cement= 0.284 x 1450 = 412kg

1 cement beg = 50 kg

No of cement begs required = 412 / 50 =8.24 ~ 8 begs

Quantity of Fine sand

Quantity of fine sand = Ratio of fine sand x volume of dry concrete / Total ratio

                                  = 1.5  x 1.56 / 5.5

                                 =0.425 cum

Unit weight of Fine sand = 1600 ~ 1800 kg/cum (Assume 1700 kg/cum)

Quantity of Fine sand= 0.425 x  1700 =722.5 kg

Quantity of Coarse aggregates

Quantity of coarse aggregate = Ratio of coarse aggregates x volume of dry concrete / Total ratio

                                  = 3 x 1.56 / 5.5

                                 =0.851 cum

Unit weight of coarse aggregate = 1500 ~ 1800 kg/cum (Assume 1650 kg/cum)

Quantity of coarse aggregates= 0.851 x 1650 =1404 kg

Amount of Water Required

The water-cement ratio depends upon the strength, climatic factors, and workability requirement of concrete.

Cement required for 1 cum of concrete = 412Kg
Assume w/c ratio = 0.50 Water required for 1 cum of concrete. = 412 x 0.5
Amount of Water Required for 1 cum of concrete = 206 kg = 206 liters

Summary

So, for a 1:1.5:3 concrete, we would need approximately:

  • 8 bags of cement
  • 0.425 cum of fine sand
  • 0.851 cum of coarse aggregate
  • 206 liters of water

Note: Please note that this calculation is approximate and can vary depending on the properties of the used materials and applicable standards in the specific region.

Automatic Calculation

Below, you can find the automatic calculator for quantity estimation, simply input values and get the result. Here a:b: c is the design concrete ratio input as 1:1.5:3 or 1:2:4 etc.

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